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Numbers

Started by (!(Tys?kan)=), 26 April, 2004, 17:40:41

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(!(Tys?kan)=)

Hi, how can I'm convert 4.93802935 to 4.39...I'm thinking like's strfind(4.93802935,"(%x+.%x)")
--Ty--

NotRabidWombat

#1
More efficient:
function Round(iNumber)
   assert(type(iNumber) == "number");
   return floor( iNumber + 0.5 );
end
Round is designed to round the first place after the decimal. So you would use:

local myNumber = 4.93802935;
myNumber = Round( mNumber * 100 ) / 100;

Just presenting concept here. Haven't actually tested.

Future functionality questions > http://www.lua.org/manual/4.0/manual.html

-NotRabidWombat


I like childish behavior. Maybe this post will be deleted next.

(!(Tys?kan)=)

--Ty--

Xico

what about:

   myNimber =  4.93802935
   myNimber = format("%0.2f", myNimber )

u will get 4.93

NotRabidWombat

#4
Yes that will also work. However the return result is a string. I was assuming he wanted rounding rather than truncation.

-NotRabidWombat


I like childish behavior. Maybe this post will be deleted next.

Xico

#5
local myNumber = 4.93802935
myNumber= format("%0.2f", myNumber)

you will get (and I typed it wrong) 4.94

local myNumber = 4.93328029
myNumber= format("%0.2f", myNumber)

you will get 4.93


and round() is not a Lua interface

NotRabidWombat

Ah cool. Did not know format would handle that.

"and round() is not a Lua interface"

I don't understand your point. It's a function that I just wrote.

-NotRabidWombat


I like childish behavior. Maybe this post will be deleted next.

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